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1 Fig 1.1 shows a speed-time graph for a car. (a) Use the graph in Fig 1.1 to (i) describe the motion of the car from 0 to 50s (ii) describe the motion of the car from 50 s to 90 s, (iii) calculate the total distance travelled by the car for the entire journey

Physics

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  1. Calculate the distance travelled during the first phase (0 s to 50 s).

    This phase is represented by a rectangle on the speed-time graph.

    Distance1=speed×time\text{Distance}_1 = \text{speed} \times \text{time} Distance1=6 m/s×50 s=300 m\text{Distance}_1 = 6\, \text{m/s} \times 50\, \text{s} = 300\, \text{m}

  2. Calculate the distance travelled during the second phase (50 s to 90 s).

    This phase is represented by a triangle on the speed-time graph.

    Distance2=12×base×height\text{Distance}_2 = \frac{1}{2} \times \text{base} \times \text{height} Distance2=12×(90 s−50 s)×6 m/s\text{Distance}_2 = \frac{1}{2} \times (90\, \text{s} - 50\, \text{s}) \times 6\, \text{m/s} Distance2=12×40 s×6 m/s=120 m\text{Distance}_2 = \frac{1}{2} \times 40\, \text{s} \times 6\, \text{m/s} = 120\, \text{m}

  3. Calculate the total distance travelled.

    Total distance=Distance1+Distance2\text{Total distance} = \text{Distance}_1 + \text{Distance}_2 Total distance=300 m+120 m=420 m\text{Total distance} = 300\, \text{m} + 120\, \text{m} = 420\, \text{m}

    The total distance travelled by the car for the entire journey is 420 m\boxed{\text{420 m}}.

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