A constant mass of gas maintained at constant pressure has a volume of 2.5×10⁴ at 0°c and 3.15×10⁴ at 100°c and 6.52×10⁴ at normal boiling point of sulphur the temperature corresponding to the boiling point of sulphur is

For a constant mass of gas maintained at constant pressure, the volume ($V$) is linearly related to the Celsius temperature ($T_C$). This relationship can be expressed as $V = aT_C + b$, where $a$ and $b$ are constants.

We have two known points:

1. At $T_C = 0^\circ C$, $V = 2.5 \times 10^4$.
2. At $T_C = 100^\circ C$, $V = 3.15 \times 10^4$.

Substitute the first point into the equation:

Substitute the second point and the value of $b$ into the equation:

So, the relationship between volume and temperature is:

We are given that the volume at the normal boiling point of sulfur is $V = 6.52 \times 10^4$. Let this temperature be $T_S$.
Substitute this volume into the derived equation:

Rounding to three significant figures, consistent with the input data:

The temperature corresponding to the boiling point of sulfur is $\boxed{618^\circ C}$.