An object whose mass is 43 kg is hanging on a thin wire the object has a potential energy of 3160.5 j how high is the object above ground

Physics

ScanSolve AI Answer

Answer

7.5 m7.5\ \text{m}

Step-by-step solution

3 steps

The object is 7.5 meters above the ground.

  1. Identify knowns and formula

    We are given the mass (mm), potential energy (PEPE), and we know the acceleration due to gravity (gg). We need to find the height (hh).
    The formula for gravitational potential energy is:

    PE=mghPE = mgh

    Where:
    PE=3160.5 JPE = 3160.5\ \text{J}
    m=43 kgm = 43\ \text{kg}
    g=9.8 m/s2g = 9.8\ \text{m/s}^2 (standard acceleration due to gravity)

  2. Rearrange the formula to solve for height

    To find hh, we can rearrange the formula:

    h=PEmgh = \frac{PE}{mg}
  3. Substitute values and calculate

    Substitute the given values into the rearranged formula:

    h=3160.5 J(43 kg)(9.8 m/s2)h = \frac{3160.5\ \text{J}}{(43\ \text{kg})(9.8\ \text{m/s}^2)} h=3160.5 J421.4 kg⋅m/s2h = \frac{3160.5\ \text{J}}{421.4\ \text{kg} \cdot \text{m/s}^2} h=7.5 mh = 7.5\ \text{m}

    The height of the object above the ground is:

    7.5 m7.5\ \text{m}
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