Diketahui sistem katrol licin, m A= 3 kg, m B = 2 kg dan percepatan gravitasi g = 10 m.s⁻². Tentukan besar: a. Percepatan sistem benda b. Tegangan tali T

The weight of an object is given by $w = m \cdot g$.

$$w_A = m_A \cdot g = 3 \text{ kg} \times 10 \text{ m/s}^2 = 30 \text{ N}$$ $$w_B = m_B \cdot g = 2 \text{ kg} \times 10 \text{ m/s}^2 = 20 \text{ N}$$

Using the formula provided for a frictionless pulley system where $m_A > m_B$:

$$a = \frac{w_A - w_B}{m_A + m_B}$$ $$a = \frac{30 \text{ N} - 20 \text{ N}}{3 \text{ kg} + 2 \text{ kg}}$$ $$a = \frac{10 \text{ N}}{5 \text{ kg}}$$ $$a = \boxed{\text{2 m/s}^2}$$

We can use the equation of motion for either mass A or mass B. Let's use mass B, which is accelerating upwards.
The net force on mass B is $T - w_B = m_B \cdot a$.

$$T = w_B + m_B \cdot a$$ $$T = 20 \text{ N} + (2 \text{ kg} \times 2 \text{ m/s}^2)$$ $$T = 20 \text{ N} + 4 \text{ N}$$ $$T = \boxed{\text{24 N}}$$