This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Here are the solutions to the problems. 97. Step 1: Calculate the total output power of the light bulbs. The transformer lights up four 12 V, 24 W light bulbs. Total output power (P_out) = Number of bulbs × Power per bulb P_out = 4 × 24 \, W P_out = 96 \, W Step 2: Determine the input power to the transformer. From problem 98, the transformer takes 0.55 \, A from a 240 \, V mains. This is the input power (P_in). P_in = V_mains × I_mains P_in = 240 \, V × 0.55 \, A P_in = 132 \, W Step 3: Calculate the efficiency of the transformer. Efficiency () is the ratio of output power to input power, expressed as a percentage. = P_outP_in × 100\% = 96 \, W132 \, W × 100\% ≈ 0.727272 × 100\% ≈ 72.73\% The efficiency of the transformer is 72.73\%. 98. Step 1: Identify the given input voltage and input current. The transformer supplies 12 \, V (output) from a 240 \, V mains (input voltage, V_p). It takes 0.55 \, A from the mains (input current, I_p). Step 2: Calculate the power delivered to the transformer (input power). The power delivered to the transformer (P_in) is the product of the input voltage and input current. P_in = V_p × I_p P_in = 240 \, V × 0.55 \, A P_in = 132 \, W The power delivered to the transformer is 132 W. 99. Step 1: Identify the given values. Resistance of the cable (R) = 0.5 \, . Electricity generated (P_gen) = 11 \, kW = 11000 \, W. Transmission voltage (V) = 120 \, V. Step 2: Calculate the current flowing through the cable during transmission. The current (I) can be found using the formula P = V I. I = P_genV I = 11000 \, W120 \, V I ≈ 91.6667 \, A Step 3: Calculate the power wasted in the cable. The power wasted (P_wasted) due to the resistance of the cable is given by P_wasted = I^2 R. P_wasted = (91.6667 \, A)^2 × 0.5 \, P_wasted = 8402.78 × 0.5 \, W P_wasted = 4201.39 \, W To express in kilowatts: P_wasted = (4201.39)/(1000) \, kW P_wasted ≈ 4.20 \, kW The power wasted in the cable is 4.20 kW. Last free one today — make it count tomorrow, or type /upgrade for unlimited.