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Identify the given values for the transformer.

Physics

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Answer

13.33A\text{13.33A}

Step-by-step solution

3 steps

C

  1. Identify the given values for the transformer.

    Primary voltage, Vp=200 VV_p = 200 \text{ V}
    Primary current, Ip=30 AI_p = 30 \text{ A}
    Output voltage, Vs=450 VV_s = 450 \text{ V}
    Output current, Is=?I_s = ?

  2. Apply the principle of conservation of power for an ideal transformer.

    For an ideal transformer, the input power equals the output power.

    Pp=PsP_p = P_s VpIp=VsIsV_p I_p = V_s I_s
  3. Substitute the known values into the equation and solve for the output current IsI_s.

    (200 V)×(30 A)=(450 V)×Is(200 \text{ V}) \times (30 \text{ A}) = (450 \text{ V}) \times I_s 6000 VA=450 V×Is6000 \text{ VA} = 450 \text{ V} \times I_s Is=6000 VA450 VI_s = \frac{6000 \text{ VA}}{450 \text{ V}} Is=60045 AI_s = \frac{600}{45} \text{ A} Is=403 AI_s = \frac{40}{3} \text{ A} Is≈13.33 AI_s \approx 13.33 \text{ A}

    The output current is approximately 13.33 A13.33 \text{ A}. This matches option C.

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