This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Question 10: Electric charge occurs only in separate parcels of a fundamental unit. This phenomenon is known as the quantization of charge. The smallest unit of charge is the elementary charge, which is the magnitude of the charge of a single electron or proton. The correct option is A. A. of ± 1.6 × 10^-19 C Question 11: Step 1: Identify the given values and Coulomb's Law. We are given two charges q_1 = q_2 = +2.0 × 10^-9 C and the distance between them r = 3.0 mm = 3.0 × 10^-3 m. Coulomb's constant is k = 8.99 × 10^9 N·m^2/C^2. Coulomb's Law states F = k (|q_1 q_2|)/(r^2). Step 2: Substitute the values into Coulomb's Law. F = (8.99 × 10^9 N·m^2/C^2) (2.0 × 10^-9 C)(2.0 × 10^-9 C)(3.0 × 10^-3 m)^2 Step 3: Calculate the force. F = (8.99 × 10^9) 4.0 × 10^-189.0 × 10^-6 N F = (8.99 × 10^9) (0.444... × 10^-12) N F ≈ 4.0 × 10^-3 N The correct option is B. B. 4 × 10^-3 N Question 12: Step 1: Identify the given values and relevant formulas. We are given the electric force F = 1.0 × 10^-5 N, the charge q = 5.0 × 10^-10 C, and the distance between the plates d = 4.0 mm = 4.0 × 10^-3 m. The electric field E is given by E = (F)/(q). For parallel plates, the potential difference V is given by V = Ed. Step 2: Calculate the electric field E. E = 1.0 × 10^-5 N5.0 × 10^-10 C E = 2.0 × 10^4 N/C Step 3: Calculate the potential difference V. V = (2.0 × 10^4 N/C) × (4.0 × 10^-3 m) V = 80 V The correct option is C. C. 80 V Question 13: Step 1: Recall the relationship between electric field and distance for a point charge. The electric field E due to a point charge is inversely proportional to the square of the distance r from the charge, i.e., E (1)/(r^2). Step 2: Set up a ratio for the electric fields at two different distances. We are given E_1 = 10 kV/m at r_1 = 10 mm. We need to find E_2 at r_2 = 20 mm. (E_2)/(E_1) = (r_1^2)/(r_2^2) Step 3: Substitute the given values and solve for E_2. (E_2)/(10 kV/m) = (10 mm)^2(20 mm)^2 (E_2)/(10 kV/m) = 100 mm^2400 mm^2 (E_2)/(10 kV/m) = (1)/(4) E_2 = (1)/(4) × 10 kV/m E_2 = 2.5 kV/m The correct option is A. A. 2.5 kV/m Question 14: For capacitors connected in parallel, the potential difference (voltage) across each individual capacitor is the same as the total potential difference across the entire parallel combination. The correct option is C. C. potential difference across each capacitor That's 2 down. 3 left today — send the next one.