Formula for number of oscillations of simple pendulum

Physics

ScanSolve AI Answer

Answer

N=t2πLgN = \frac{t}{2\pi \sqrt{\frac{L}{g}}}

Step-by-step solution

3 steps

The formula for the number of oscillations NN of a simple pendulum is derived from its period TT.

  1. Recall the definition of period.

    The period TT is the time taken for one complete oscillation. If a pendulum completes NN oscillations in a total time tt, then the period is given by:

    T=tNT = \frac{t}{N}
  2. Rearrange the formula to solve for the number of oscillations NN.

    N=tTN = \frac{t}{T}
  3. Substitute the formula for the period T=2πLgT = 2\pi \sqrt{\frac{L}{g}} into the expression for NN.

    N=t2πLgN = \frac{t}{2\pi \sqrt{\frac{L}{g}}}

    Where:

    • NN is the number of oscillations.
    • tt is the total time over which the oscillations are counted.
    • LL is the length of the pendulum.
    • gg is the acceleration due to gravity.
    • π\pi is the mathematical constant pi.

    The formula for the number of oscillations of a simple pendulum is:

    N=t2πLg\boxed{N = \frac{t}{2\pi \sqrt{\frac{L}{g}}}}

    One more to go today! Send it over.

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