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Calculate the friction force on an object with a mass of 25 kg and a coefficient of friction of 0.2.

Physics

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Answer

49 N\text{49 N}

Step-by-step solution

3 steps
  1. Identify the given values for object A.

    The mass of object A is mA=25 kgm_A = 25 \text{ kg}.
    The coefficient of friction is μ=0.2\mu = 0.2.
    The acceleration due to gravity is g=9.8 m/s2g = 9.8 \text{ m/s}^2.

  2. Calculate the normal force (NN) acting on object A.

    Since object A is on a horizontal surface, the normal force is equal to its weight.

    N=mAgN = m_A g N=(25 kg)×(9.8 m/s2)N = (25 \text{ kg}) \times (9.8 \text{ m/s}^2) N=245 NN = 245 \text{ N}
  3. Calculate the friction force (FfF_f) on object A.

    The friction force is given by the formula Ff=μNF_f = \mu N.

    Ff=(0.2)×(245 N)F_f = (0.2) \times (245 \text{ N}) Ff=49 NF_f = 49 \text{ N}

    The friction force on object A is 49 N\text{49 N}.

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