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I) To calculate the current drawn, we use the formula relating power, voltage, and current: P = V x I.

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2 parts
b(i)

0.42 A\text{0.42 A}

b(ii)

576 Ω\text{576 } \Omega

Step-by-step solution

4 steps

Here's the solution for question 1(b):

Part b(i)· 2 steps

To calculate the current drawn, we use the formula relating power, voltage, and current: P=V×IP = V \times I.

  1. State the given values and the formula.

    Given:
    Power (PP) = 100 W100\, \text{W}
    Voltage (VV) = 240 V240\, \text{V}
    Formula: I=PVI = \frac{P}{V}

  2. Substitute the values into the formula and calculate the current.

    I=100 W240 VI = \frac{100\, \text{W}}{240\, \text{V}} I=0.4166... AI = 0.4166...\, \text{A} I≈0.42 AI \approx \boxed{\text{0.42 A}}

Part b(ii)

576 Ω\text{576 } \Omega

To calculate the resistance of the heater, we can use the formula relating power, voltage, and resistance: P=V2RP = \frac{V^2}{R}.

  1. State the given values and the formula.

    Given:
    Power (PP) = 100 W100\, \text{W}
    Voltage (VV) = 240 V240\, \text{V}
    Formula: R=V2PR = \frac{V^2}{P}

  2. Substitute the values into the formula and calculate the resistance.

    R=(240 V)2100 WR = \frac{(240\, \text{V})^2}{100\, \text{W}} R=57600 V2100 WR = \frac{57600\, \text{V}^2}{100\, \text{W}} R=576 ΩR = \boxed{\text{576 } \Omega}
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