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Calculate the impedance and power factor of Coil 1. Given V = 200 V, I1 = 15 A, P1 = 2800 W.

Physics

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Step 1: Determine the parameters of Coil 1.
Given:
Supply voltage V=200 VV = 200 \text{ V}
Current I1=15 AI_1 = 15 \text{ A}
Power dissipated P1=2800 WP_1 = 2800 \text{ W}

The power dissipated in an AC circuit is given by P=VIcos⁡ϕP = V I \cos \phi.
For Coil 1:

P1=VI1cos⁡ϕ1P_1 = V I_1 \cos \phi_1 2800 W=200 V×15 A×cos⁡ϕ12800 \text{ W} = 200 \text{ V} \times 15 \text{ A} \times \cos \phi_1
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