Initial velocity, u = 0 m/s (assuming the technician starts from rest)

Question

ScanSolve AI Tutor · Accepted Answer

Here's how to solve part (a) of the problem.

Given:

Initial velocity, $u = 0 \text{ m/s}$ (assuming the technician starts from rest)
Height, $h = 80 \text{ m}$
Acceleration due to gravity, $g = 10 \text{ m/s}^2$

We need to find the time, $t$ .

Identify the appropriate kinematic equation.
To find the time when initial velocity, displacement, and acceleration are known, we use the equation:
$h = ut + \frac{1}{2}gt^2$
Substitute the given values into the equation.
$80 \text{ m} = (0 \text{ m/s})t + \frac{1}{2}(10 \text{ m/s}^2)t^2$
Simplify the equation and solve for $t^2$ .
$80 \text{ m} = 0 + (5 \text{ m/s}^2)t^2$ $80 \text{ m} = (5 \text{ m/s}^2)t^2$ $t^2 = \frac{80 \text{ m}}{5 \text{ m/s}^2}$ $t^2 = 16 \text{ s}^2$
Calculate $t$ by taking the square root.
$t = \sqrt{16 \text{ s}^2}$ $t = 4 \text{ s}$
The time it takes for the technician to hit the ground is $\text{4 s}$ .

• Initial velocity, u = 0 m/s (assuming the technician starts from rest)