This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Here are the solutions to Question 7: QUESTION 7: HEAT 7.1 Describe the isothermal process. An isothermal process is a thermodynamic process during which the temperature of a system remains constant. This occurs when the system is in thermal contact with a large heat reservoir, allowing heat to be exchanged to maintain a steady temperature. 7.2 A right rectangular prism of cast iron has dimensions of 55 × 45 × 35 mm at 25^ C. The prism is heated to 88^ C. The coefficient of linear expansion of cast iron is 9 × 10^-6/^ C. Given: Initial dimensions: L_0 = 55 mm, W_0 = 45 mm, H_0 = 35 mm Initial temperature, T_1 = 25^ C Final temperature, T_2 = 88^ C Coefficient of linear expansion, = 9 × 10^-6/^ C 7.2.1 The increase in volume Step 1: Calculate the original volume (V_0). V_0 = L_0 × W_0 × H_0 V_0 = 55 mm × 45 mm × 35 mm V_0 = 86625 mm^3 Step 2: Calculate the change in temperature ( T). T = T_2 - T_1 T = 88^ C - 25^ C = 63^ C Step 3: Calculate the coefficient of volumetric expansion (). For isotropic materials, the coefficient of volumetric expansion is approximately three times the coefficient of linear expansion. = 3 = 3 × (9 × 10^-6/^ C) = 27 × 10^-6/^ C Step 4: Calculate the increase in volume ( V). V = V_0 T V = (86625 mm^3) × (27 × 10^-6/^ C) × (63^ C) V = 147.303375 mm^3 The increase in volume is 147.30 mm^3. 7.2.2 The volume at 88^ C Step 1: Calculate the final volume (V_f). V_f = V_0 + V V_f = 86625 mm^3 + 147.303375 mm^3 V_f = 86772.303375 mm^3 The volume at 88^ C is 86772.30 mm^3. Send me the next one 📸