This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Here are the solutions for the next set of questions. Question 15: Step 1: Determine the resistance of a single resistor from the parallel combination. Let R be the resistance of each identical resistor. For two identical resistors in parallel, the equivalent resistance R_eq,p is given by: (1)/(R_eq,p) = (1)/(R) + (1)/(R) = (2)/(R) We are given R_eq,p = 10 . (1)/(10 ) = (2)/(R) R = 2 × 10 = 20 Step 2: Calculate the equivalent resistance when these resistors are connected in series. For resistors in series, the equivalent resistance R_eq,s is the sum of individual resistances: R_eq,s = R + R = 2R R_eq,s = 2 × 20 = 40 The correct option is C. C. 40 Question 16: Step 1: Identify the given capacitances. The capacitance in air is C_air = 20 . The capacitance with the dielectric is C_dielectric = 42 . Step 2: Use the formula relating capacitance with and without a dielectric. The dielectric constant is defined as the ratio of the capacitance with the dielectric to the capacitance in air: = C_dielectricC_air Step 3: Calculate the dielectric constant. = 42 20 = 2.1 The correct option is C. C. 2.1 Question 17: Step 1: Identify the given values and the formula for work done. We are given the charge q = 2.0 C and the potential difference V = 12 V. The work done W in moving a charge q against a potential difference V is given by: W = qV Step 2: Substitute the values and calculate the work done. W = (2.0 C) × (12 V) W = 24 J The correct option is C. C. 24 J Question 18: Step 1: Identify the given values and the formula for power dissipated. We are given the resistance R = 50 and the current I = 2 A. The power P dissipated as heat in a resistor is given by: P = I^2 R Step 2: Substitute the values and calculate the power. P = (2 A)^2 × 50 P = 4 A^2 × 50 P = 200 W The correct option is C. C. 200 W Question 19: Kirchhoff's first law, also known as Kirchhoff's Current Law (KCL) or the junction rule, states that the algebraic sum of currents entering a junction (or node) is equal to the algebraic sum of currents leaving the junction. This law is a direct consequence of the conservation of charges. The correct option is D. D. charges Question 20: The amount of work done in bringing a unit positive charge from infinity to a point in an electric field is the definition of Electric potential. The correct option is A. A. Electric potential 3 done, 2 left today. You're making progress.