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The instructor later asks learners to explain the motion of the vehicle using the velocity-time graph provided, determine whether the driver should be penalized and explain the importance of seat belts.

Physics

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Hapa kuna majibu kwa ITEM 5:

ITEM 5

  1. Eleza mwendo wa gari kwa kutumia grafu ya kasi-muda.

    • Sehemu A (sekunde 0 hadi 12.5): Gari linaongeza kasi kwa kasi isiyobadilika kutoka 0 m/s0\, \text{m/s} hadi 12.5 m/s12.5\, \text{m/s}. Hii inaonyesha kuongeza kasi chanya.
    • Sehemu B (sekunde 12.5 hadi 27.5): Gari linasafiri kwa kasi isiyobadilika ya 12.5 m/s12.5\, \text{m/s}. Hii inaonyesha kasi sifuri (mwendo wa kasi isiyobadilika).
    • Sehemu C (sekunde 27.5 hadi 42.5): Gari linapunguza kasi kwa kasi isiyobadilika kutoka 12.5 m/s12.5\, \text{m/s} hadi 0 m/s0\, \text{m/s}. Hii inaonyesha kupunguza kasi (negative acceleration).
  2. Kokotoa kasi ya wastani na uamue kama dereva anapaswa kuadhibiwa.

    Kasi ya wastani = Jumla ya umbali / Jumla ya muda.
    Jumla ya muda = 42.5 s42.5\, \text{s}.
    Jumla ya umbali ni eneo chini ya grafu ya kasi-muda.

    Eneo A (Pembetatu):

    UmbaliA=12×msingi×urefu=12×12.5 s×12.5 m/s=78.125 m\text{Umbali}_A = \frac{1}{2} \times \text{msingi} \times \text{urefu} = \frac{1}{2} \times 12.5\, \text{s} \times 12.5\, \text{m/s} = 78.125\, \text{m}

    Eneo B (Mstatili):

    UmbaliB=urefu×upana=(27.5 s−12.5 s)×12.5 m/s=15 s×12.5 m/s=187.5 m\text{Umbali}_B = \text{urefu} \times \text{upana} = (27.5\, \text{s} - 12.5\, \text{s}) \times 12.5\, \text{m/s} = 15\, \text{s} \times 12.5\, \text{m/s} = 187.5\, \text{m}

    Eneo C (Pembetatu):

    UmbaliC=12×msingi×urefu=12×(42.5 s−27.5 s)×12.5 m/s=12×15 s×12.5 m/s=93.75 m\text{Umbali}_C = \frac{1}{2} \times \text{msingi} \times \text{urefu} = \frac{1}{2} \times (42.5\, \text{s} - 27.5\, \text{s}) \times 12.5\, \text{m/s} = \frac{1}{2} \times 15\, \text{s} \times 12.5\, \text{m/s} = 93.75\, \text{m}

    Jumla ya umbali:

    Jumla ya umbali=78.125 m+187.5 m+93.75 m=359.375 m\text{Jumla ya umbali} = 78.125\, \text{m} + 187.5\, \text{m} + 93.75\, \text{m} = 359.375\, \text{m}

    Kasi ya wastani:

    Kasi ya wastani=359.375 m42.5 s≈8.46 m/s\text{Kasi ya wastani} = \frac{359.375\, \text{m}}{42.5\, \text{s}} \approx 8.46\, \text{m/s}

    Kwa kuwa kasi ya wastani (8.46 m/s8.46\, \text{m/s}) ni chini ya 10 m/s10\, \text{m/s}, dereva hapaswi kuadhibiwa.

  3. Eleza umuhimu wa mikanda ya usalama.

    Mikanda ya usalama ni muhimu kwa sababu:

    • Inazuia abiria kutupwa mbele wakati wa kusimama ghafla au ajali, kutokana na inertia.
    • Inasambaza nguvu ya athari kwenye eneo kubwa la mwili, kupunguza ukali wa majeraha.
    • Inawaweka abiria salama kwenye viti vyao, kuzuia kugonga sehemu ngumu ndani ya gari au kutupwa nje ya gari.
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