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A student burns 60.5 g of charcoal (carbon) in excess oxygen. a) Identify the product and explain why it is a covalent compound. b) Explain if the product is suitable for cooking. c) Calculate the vol

Chemistry

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Answer

c

112.93 L112.93 \, \text{L}

Step-by-step solution

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Part a

The product formed is carbon dioxide (CO2\text{CO}_2). It is a covalent compound because it is formed by the sharing of electrons between carbon and oxygen atoms, both of which are non-metals.

Part b

The product, carbon dioxide, is a gas. It is not suitable for cooking as it does not contribute to the heating process and can displace oxygen in poorly ventilated areas, posing a health risk.

Part c

112.93 L112.93 \, \text{L}

  1. Calculate the molar mass of charcoal (carbon).

    The molar mass of carbon (C) is 12 g/mol12 \, \text{g/mol}.

  2. Calculate the number of moles of charcoal used.

    Given mass of charcoal = 60.5 g60.5 \, \text{g}.

    Moles of C=MassMolar mass=60.5 g12 g/mol=5.04166... mol\text{Moles of C} = \frac{\text{Mass}}{\text{Molar mass}} = \frac{60.5 \, \text{g}}{12 \, \text{g/mol}} = 5.04166... \, \text{mol}

  3. Determine the moles of carbon dioxide produced.

    From the balanced equation C(s)+O2(g)→CO2(g)\text{C(s)} + \text{O}_2\text{(g)} \to \text{CO}_2\text{(g)}, the mole ratio of C to CO2\text{CO}_2 is 1:11:1.
    So, moles of CO2\text{CO}_2 produced = 5.04166... mol5.04166... \, \text{mol}.

  4. Calculate the volume of carbon dioxide produced at s.t.p.

    At s.t.p., 1 mole of any gas occupies 22.4 L22.4 \, \text{L}.

    Volume of CO2=Moles of CO2×Molar volume at s.t.p.\text{Volume of CO}_2 = \text{Moles of CO}_2 \times \text{Molar volume at s.t.p.} Volume of CO2=5.04166... mol×22.4 L/mol=112.933... L\text{Volume of CO}_2 = 5.04166... \, \text{mol} \times 22.4 \, \text{L/mol} = 112.933... \, \text{L}

    Rounding to two decimal places:

    Volume of CO2=112.93 L\text{Volume of CO}_2 = \boxed{112.93 \, \text{L}}

    d) Yes, carbon dioxide has several environmental impacts. It is a greenhouse gas that contributes to global warming and climate change. It also dissolves in water to form carbonic acid, leading to ocean acidification, which harms marine life.

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