We read your photo as:

Determine the enthalpy of formation of calcium carbonate. Some average bond energies are given below. Calculate the energy change for the reaction below.

Chemistry

ScanSolve AI Answer

Answer

c

−115 kJ/mol-115 \text{ kJ/mol}

Step-by-step solution

4 steps

Haya, tuendelee na maswali haya.

Part ii

Bainisha entalpia ya uundaji wa kalsiamu kabonati.

Samahani, swali hili haliwezi kujibiwa kwa sababu hakuna data ya kutosha (kama vile entalpia za uundaji wa viambato vingine au entalpia za miitikio) iliyotolewa kwenye picha.

Part c

−115 kJ/mol-115 \text{ kJ/mol}

Kokotoa mabadiliko ya nishati kwa mwitikio ufuatao

C2H6(g)+Cl2(g)→CH3CH2Cl(g)+HCl(g)\text{C}_2\text{H}_6(\text{g}) + \text{Cl}_2(\text{g}) \to \text{CH}_3\text{CH}_2\text{Cl}(\text{g}) + \text{HCl}(\text{g})

  1. Tambua vifungo vilivyovunjwa na vilivyoundwa.

    Katika mwitikio huu, kifungo kimoja cha C-H katika C2H6\text{C}_2\text{H}_6 na kifungo kimoja cha Cl-Cl katika Cl2\text{Cl}_2 vinavunjwa. Kifungo kimoja cha C-Cl katika CH3CH2Cl\text{CH}_3\text{CH}_2\text{Cl} na kifungo kimoja cha H-Cl katika HCl\text{HCl} vinaundwa.

  2. Kokotoa jumla ya nishati inayohitajika kuvunja vifungo.

    Nishati ya vifungo vilivyovunjwa:

    • C-H: 414 kJ/mol414 \text{ kJ/mol}
    • Cl-Cl: 243 kJ/mol243 \text{ kJ/mol} Jumla ya nishati inayohitajika kuvunja vifungo = 414 kJ/mol+243 kJ/mol=657 kJ/mol414 \text{ kJ/mol} + 243 \text{ kJ/mol} = 657 \text{ kJ/mol}

  3. Kokotoa jumla ya nishati inayotolewa wakati vifungo vinaundwa.

    Nishati ya vifungo vilivyoundwa:

    • C-Cl: 432 kJ/mol432 \text{ kJ/mol}
    • H-Cl: 340 kJ/mol340 \text{ kJ/mol} Jumla ya nishati inayotolewa wakati vifungo vinaundwa = 432 kJ/mol+340 kJ/mol=772 kJ/mol432 \text{ kJ/mol} + 340 \text{ kJ/mol} = 772 \text{ kJ/mol}

  4. Kokotoa mabadiliko ya nishati (ΔH\Delta H) kwa mwitikio.

    ΔH=(Jumla ya nishati ya vifungo vilivyovunjwa)−(Jumla ya nishati ya vifungo vilivyoundwa)\Delta H = (\text{Jumla ya nishati ya vifungo vilivyovunjwa}) - (\text{Jumla ya nishati ya vifungo vilivyoundwa}) ΔH=657 kJ/mol−772 kJ/mol\Delta H = 657 \text{ kJ/mol} - 772 \text{ kJ/mol} ΔH=−115 kJ/mol\Delta H = \boxed{-115 \text{ kJ/mol}}

    5.a) Fafanua neno umumunyifu.
    Umumunyifu ni kiasi cha juu zaidi cha dutu mumunyifu (solute) kinachoweza kuyeyuka katika kiasi fulani cha kimumunyishaji (solvent) kwenye joto maalum ili kuunda ufumbuzi uliokolea (saturated solution).

    5.b) Katika jaribio la kubainisha umumunyifu wa chumvi mbili X na Y kwenye joto tofauti, mwanafunzi alirekodi uchunguzi wake kama inavyoonyeshwa hapa chini.
    Jedwali la data limetolewa, lakini hakuna swali maalum lililoulizwa kuhusu data hii.

Was this helpful?

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question

More Chemistry Questions

QTo calculate the enthalpy change ( H) for the reaction C + O2 -> CO2 using bond energies, we use the…Q1 Explain why the reaction is exothermic. 15.2 Calculate the average rate of reaction. 15.3…QTo determine the enthalpy change for the reaction using bond energies, we use the formula:QCalculate the enthalpy change for the reaction C2H4 + H2 -> C2H6 using the provided bond energies.QCalculate the enthalpy change of the reaction C3H8(g) + 5O2(g) -> 3CO2(g) + 4H2O(l) using the given…
See all Chemistry questions →
Got a syllabus? Photograph it and I'll tell you what's due and what's worth the most.
Handwritten step-by-step solution preview

Handwritten Step-by-Step Solution

Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.

Try on WhatsApp