This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
The diagram illustrates an electrical circuit used to investigate a science experiment. The rheostat is adjusted to vary the current and voltage in the circuit. Fig 2 (a) and Fig 2 (b) below illustrate ammeter readings I=I1, I2, I3, I4, I5 and voltmeter readings v=v1, v2, v3, v4, and v5, in table 1 below respectively when the key is closed.
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Answer
R = 5.0 \Omega
Step 1: Read and record the ammeter readings from Fig. 2(a).
The meter scales show the following values for the needle positions:
Step 2: Read and record the voltmeter readings from Fig. 2(b).
The meter scales show the following values for the needle positions (in volts):
Step 3: Verify Ohm's law using .
For low setting:
For medium setting:
For high setting:
Average resistance .
Step 4: Plot the graph with (vertical axis, in A) vs (horizontal axis, in V).
Plot the points: , , .
The graph is a straight line through origin with slope .
R = 5.0 \Omega
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Read and record the ammeter readings from Fig. 2(a).
ScanSolve AI Answer
Step 1: Read and record the ammeter readings from Fig. 2(a). The meter scales show the following values for the needle positions: |c|c|c| I_L & I_M & I_R \\ 0.20~A & 0.40~A & 0.60~A \\ Step 2: Read and record the voltmeter readings from Fig. 2(b). The meter scales show the following values for the needle positions (in volts): |c|c|c| V_L & V_M & V_R \\ 1.0~V & 2.0~V & 3.0~V \\ Step 3: Verify Ohm's law using V = IR. For low setting: R = V_LI_L = (1.0)/(0.20) = 5.0~ For medium setting: R = V_MI_M = (2.0)/(0.40) = 5.0~ For high setting: R = V_RI_R = (3.0)/(0.60) = 5.0~ Average resistance R = 5.0~. Step 4: Plot the graph with I (vertical axis, in A) vs V (horizontal axis, in V). Plot the points: (1.0, 0.20), (2.0, 0.40), (3.0, 0.60). The graph is a straight line through origin with slope (1)/(R) = 0.20~A/V. R = 5.0