The diagram illustrates an electrical circuit used to investigate a science experiment. The rheostat is adjusted to vary the current and voltage in the circuit. Fig 2 (a) and Fig 2 (b) below illustrate ammeter readings I=I1, I2, I3, I4, I5 and voltmeter readings v=v1, v2, v3, v4, and v5, in table 1 below respectively when the key is closed.

Physics
The diagram illustrates an electrical circuit used to investigate a science experiment. The rheostat is adjusted to vary the current and voltage in the circuit. Fig 2 (a) and Fig 2 (b) below illustrate ammeter readings I=I1, I2, I3, I4, I5 and voltmeter readings v=v1, v2, v3, v4, and v5, in table 1 below respectively when the key is closed.

ScanSolve AI Answer

Answer

R = 5.0 \Omega

Step 1: Read and record the ammeter readings from Fig. 2(a).

The meter scales show the following values for the needle positions:

ILIMIR0.20 A0.40 A0.60 A\begin{array}{|c|c|c|} \hline I_L & I_M & I_R \\ \hline 0.20~A & 0.40~A & 0.60~A \\ \hline \end{array}

Step 2: Read and record the voltmeter readings from Fig. 2(b).

The meter scales show the following values for the needle positions (in volts):

VLVMVR1.0 V2.0 V3.0 V\begin{array}{|c|c|c|} \hline V_L & V_M & V_R \\ \hline 1.0~V & 2.0~V & 3.0~V \\ \hline \end{array}

Step 3: Verify Ohm's law using V=IRV = IR.

For low setting:
R=VLIL=1.00.20=5.0 ΩR = \frac{V_L}{I_L} = \frac{1.0}{0.20} = 5.0~\Omega

For medium setting:
R=VMIM=2.00.40=5.0 ΩR = \frac{V_M}{I_M} = \frac{2.0}{0.40} = 5.0~\Omega

For high setting:
R=VRIR=3.00.60=5.0 ΩR = \frac{V_R}{I_R} = \frac{3.0}{0.60} = 5.0~\Omega

Average resistance R=5.0 ΩR = 5.0~\Omega.

Step 4: Plot the graph with II (vertical axis, in A) vs VV (horizontal axis, in V).

Plot the points: (1.0,0.20)(1.0, 0.20), (2.0,0.40)(2.0, 0.40), (3.0,0.60)(3.0, 0.60).

The graph is a straight line through origin with slope 1R=0.20 A/V\frac{1}{R} = 0.20~\mathrm{A/V}.

R = 5.0 \Omega

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Quick Answer

Read and record the ammeter readings from Fig. 2(a).

The diagram illustrates an electrical circuit used to investigate a science experiment. The rheostat is adjusted to vary the current and voltage in the circuit. Fig 2 (a) and Fig 2 (b) below illustrate ammeter readings I=I1, I2, I3, I4, I5 and voltmeter readings v=v1, v2, v3, v4, and v5, in table 1 below respectively when the key is closed.
Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI Answer
Step 1: Read and record the ammeter readings from Fig. 2(a). The meter scales show the following values for the needle positions: |c|c|c| I_L & I_M & I_R \\ 0.20~A & 0.40~A & 0.60~A \\ Step 2: Read and record the voltmeter readings from Fig. 2(b). The meter scales show the following values for the needle positions (in volts): |c|c|c| V_L & V_M & V_R \\ 1.0~V & 2.0~V & 3.0~V \\ Step 3: Verify Ohm's law using V = IR. For low setting: R = V_LI_L = (1.0)/(0.20) = 5.0~ For medium setting: R = V_MI_M = (2.0)/(0.40) = 5.0~ For high setting: R = V_RI_R = (3.0)/(0.60) = 5.0~ Average resistance R = 5.0~. Step 4: Plot the graph with I (vertical axis, in A) vs V (horizontal axis, in V). Plot the points: (1.0, 0.20), (2.0, 0.40), (3.0, 0.60). The graph is a straight line through origin with slope (1)/(R) = 0.20~A/V. R = 5.0