A 60.0 kg man jumps from a height of 3.00 m onto a platform that compresses 0.500 cm. What is the maximum spring constant of the platform?

March 31, 2026Physics

ScanSolve AI Answer

March 31, 2026

Answer

$60.0 \text{ kg}$

Step 1: Identify the given values and convert units.

Mass of the man ( $m$ ) = $60.0 \text{ kg}$
Initial height ( $h$ ) = $3.00 \text{ m}$
Compression distance ( $d$ ) = $0.500 \text{ cm}$
Acceleration due to gravity ( $g$ ) = $9.81 m/s^2$ (standard value)

Convert the compression distance from centimeters to meters: $d = 0.500 cm \times \frac{1 m}{100 cm} = 0.00500 \text{ m}$

Step

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Quick Answer

Identify the given values and convert units.

Asked on March 31, 2026Physics

This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.

ScanSolve AI AnswerAnswered on March 31, 2026

Step 1: Identify the given values and convert units. Mass of the man (m) = 60.0 kg Initial height (h) = 3.00 m Compression distance (d) = 0.500 cm Acceleration due to gravity (g) = 9.81 m/s^2 (standard value) Convert the compression distance from centimeters to meters: d = 0.500 cm × 1 m100 cm = 0.00500 m Step