This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
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Here are the solutions to the remaining questions: Question 2: A parallel plate capacitor has a capacitance of 10 F. If the distance between the plates is halved, what will happen to the capacitance? Step 1: Recall the formula for capacitance. The capacitance (C) of a parallel plate capacitor is given by: C = ( A)/(d) where is the permittivity of the dielectric, A is the area of the plates, and d is the distance between the plates. Step 2: Analyze the effect of halving the distance. If the distance d is halved, the new distance d' becomes (d)/(2). The new capacitance C' will be: C' = ( A)/(d') = ( A)/((d/2)) = 2 ( A)/(d) Since C = ( A)/(d), we can write: C' = 2C This means the new capacitance will be double the original capacitance. The final answer is A. It will double. --- Question 3: The graphical representation of pressure law is always a straight line passing through the origin only if the temperature scale is Concept: The pressure law (also known as Gay-Lussac's Law or Amontons's Law) states that for a fixed mass of gas at constant volume, the pressure is directly proportional to its absolute temperature. Explanation: A graph of pressure versus temperature will be a straight line passing through the origin only when the temperature is measured on an absolute scale, where zero corresponds to absolute zero. The Kelvin* scale is the absolute thermodynamic temperature scale. The final answer is B. Thermodynamic (Kelvin). --- Question 4: The density of water is 1 g/cm^3, while the density of ice is 0.9 g/cm^3. Calculate the change in volume when 90 g of ice is completely melted. Step 1: Calculate the volume of ice. The formula for volume is V = (m)/(). Given mass of ice (m_ice) = 90 g Given density of ice (_ice) = 0.9 g/cm^3 V_ice = 90 g0.9 g/cm^3 = 100 cm^3 Step 2: Calculate the volume of water. When ice melts, its mass remains the same. So, mass of water (m_water) = 90 g. Given density of water (_water) = 1 g/cm^3 V_water = 90 g1 g/cm^3 = 90 cm^3 *Step 3: