Three 4ω resistance are connected in parallel what is the equivalent resistance?

The formula for the equivalent resistance ($R_{eq}$) of resistors connected in parallel is:

$$\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ...$$

We have three resistors, each with a resistance of 4Ω. So, $R_1 = 4\Omega$, $R_2 = 4\Omega$, and $R_3 = 4\Omega$.

$$\frac{1}{R_{eq}} = \frac{1}{4\Omega} + \frac{1}{4\Omega} + \frac{1}{4\Omega}$$

Since the denominators are the same, we can add the numerators directly.

$$\frac{1}{R_{eq}} = \frac{1+1+1}{4\Omega} = \frac{3}{4\Omega}$$

To find $R_{eq}$, we take the reciprocal of both sides of the equation.

$$R_{eq} = \frac{4\Omega}{3}$$

$$R_{eq} \approx 1.33\Omega$$

The equivalent resistance is $\frac{4}{3}\Omega$.