Hey John, good to see you again. Step 1: Identify the formula for resistors in parallel. The formula for the equivalent resistance ($R_{eq}$) of resistors connected in parallel is: $$ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + ... $$ Step 2: Substitute the given values into the formula. We have three resistors, each with a resistance of 4Ω. So, $R_1 = 4\Omega$, $R_2 = 4\Omega$, and $R_3 = 4\Omega$. $$ \frac{1}{R_{eq}} = \frac{1}{4\Omega} + \frac{1}{4\Omega} + \frac{1}{4\Omega} $$ Step 3: Calculate the sum of the fractions. Since the denominators are the same, we can add the numerators directly. $$ \frac{1}{R_{eq}} = \frac{1+1+1}{4\Omega} = \frac{3}{4\Omega} $$ Step 4: Solve for $R_{eq}$. To find $R_{eq}$, we take the reciprocal of both sides of the equation. $$ R_{eq} = \frac{4\Omega}{3} $$ Step 5: Express the answer as a decimal or fraction. $$ R_{eq} \approx 1.33\Omega $$ The equivalent resistance is $\boxed{\frac{4}{3}\Omega}$. Send me the next one 📸